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=-3Y^2-9Y+1
We move all terms to the left:
-(-3Y^2-9Y+1)=0
We get rid of parentheses
3Y^2+9Y-1=0
a = 3; b = 9; c = -1;
Δ = b2-4ac
Δ = 92-4·3·(-1)
Δ = 93
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{93}}{2*3}=\frac{-9-\sqrt{93}}{6} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{93}}{2*3}=\frac{-9+\sqrt{93}}{6} $
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